Java 8 find maximum number using stream is example specified here.
Table of Contents
Example 1: stream + reduce method
package com.javadeveloperzone;
import java.util.Arrays;
/**
* Created by JavaDeveloperZone on 30-04-2017.
*/
public class MaxNumberUsingStreamWay1 {
public static void main(String... args) {
java.util.List<Integer> integer = Arrays.asList(1, 2, 15, 10, 5, 5, 10, 3, 4);
int maxNumber = integer.stream().reduce(0, (max, i) -> {
max = max < i ? i : max;
return max;
});
System.out.print("Maximum number is" + maxNumber);
}
}
Example 2: stream + max method
package com.javadeveloperzone;
import java.util.Arrays;
import java.util.Optional;
/**
* Created by JavaDeveloperZone on 30-04-2017.
*/
public class MaxNumberUsingStreamWay2 {
public static void main(String... args) {
java.util.List<Integer> integer = Arrays.asList(1, 2, 15, 10, 5, 5, 10, 3, 4);
Optional<Integer> maxNumber = integer.stream().max((number1, number2) -> {
if (number1 == number2) {
return 0;
} else if (number1 > number2) {
return 1;
} else
return -1;
});
System.out.print("Maximum number is" + maxNumber.get());
}
}
References:
https://docs.oracle.com/javase/tutorial/collections/streams/reduction.html
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